Recursive Packing Bounds for Supercritical Disconnection in Bernoulli Site Percolation

This paper establishes a quantitative upper bound on the supercritical disconnection probability for Bernoulli site percolation on infinite, connected, locally finite graphs by introducing a recursive packing number that counts essentially independent local witnesses for the disconnection event.

Original authors: Zhongyang Li

Published 2026-03-18
📖 5 min read🧠 Deep dive

This is an AI-generated explanation of the paper below. It is not written or endorsed by the authors. For technical accuracy, refer to the original paper. Read full disclaimer

Imagine you are standing in a vast, infinite city made of blocks (the graph). Each block has a light switch. You flip a switch for every block in the city: with probability pp, the light turns ON (open); otherwise, it stays OFF (closed).

In this city, if a block is ON, it can "talk" to its neighbors if they are also ON. If a chain of ON blocks stretches out forever, that block is part of an infinite highway to the horizon.

The Big Question

The paper asks a specific question: If you pick a group of blocks (a set SS), what are the odds that none of them can reach the infinite highway?

If the probability of a light turning ON (pp) is low, the city is mostly dark, and it's easy for everyone to be cut off. But what if pp is high (the "supercritical" regime)? The city is mostly lit, and infinite highways are everywhere. Intuitively, it seems impossible for a whole group of blocks to be cut off.

However, the author, Zhongyang Li, wants to know: Exactly how small is the probability of this "disconnection" event? Can we put a precise number on it?

The Problem with "One Size Fits All"

In the past, mathematicians could only give answers for very specific, perfectly symmetrical cities (like a grid or a perfect tree). If the city had weird shapes or irregular streets, the math broke down.

Li's paper introduces a new tool that works for any city, no matter how weird or irregular, as long as every block has a finite number of neighbors.

The Solution: The "Recursive Packing" Strategy

To solve this, Li invents a concept called the Recursive Packing Number. Let's break this down with a metaphor.

The Metaphor: The "Witness" Game

Imagine you are trying to prove that a specific group of blocks (SS) might get cut off from the infinite highway. To do this, you need to find "witnesses"—special blocks within your group that act as spies.

  1. The First Spy: You pick a block from your group. You draw a circle (a "witness ball") around it.

    • If this block can't reach the infinite highway, it's almost certainly because it can't even reach the edge of its own circle.
    • If it can reach the edge of the circle, it has a good chance of reaching the infinite highway.
    • You check: Does this block have a decent chance (say, at least cc) of reaching the infinite highway? If yes, it's a valid spy.
  2. The Second Spy: Now, you remove the first spy's circle from the city. You can't use that area again. You look at the remaining blocks in your group and pick a second spy.

    • You draw a new circle around this second block.
    • You check: Even with the first circle gone, does this second block still have a decent chance of reaching the infinite highway?
    • Crucially, because the circles are far apart, the "luck" of the second block is mostly independent of the first.
  3. The Packing Number: You keep doing this, picking spies one by one, removing their circles, and checking if they are still "supercritical" (likely to connect to infinity).

    • The Packing Number is simply the maximum number of spies you can fit into your group this way.

The Magic Formula

The paper proves a beautiful, simple rule:

The probability that your whole group gets cut off is roughly equal to:
(The chance a single spy fails) raised to the power of (The number of spies you packed).

Think of it like a safety net. If you have one spy, there's a small chance they fail. If you have 10 independent spies, the chance that all 10 fail at the same time is astronomically small.

The formula says:
Disconnection Probability(1c)Number of Spies \text{Disconnection Probability} \approx (1 - c)^{\text{Number of Spies}}

Where:

  • cc is the minimum chance a single spy has of connecting to infinity.
  • The "Number of Spies" is your Recursive Packing Number.

Why This is a Big Deal

  1. It Works Everywhere: Whether your city is a perfect grid, a random mess, or a tree with weird branches, this method works. You just need to count how many "independent spies" you can pack into your group.
  2. It's Explicit: The paper shows how to calculate this number for specific types of trees.
    • Example: On a regular tree (like a perfect family tree), if you pick blocks that are far enough apart, the Packing Number is exactly the number of blocks you picked.
    • Example: Even on a "decorated" tree (where the main path is regular, but the side branches are weird), the math still holds up.

The Takeaway

This paper gives us a universal "ruler" to measure how hard it is to disconnect a group of points in a random network.

Instead of getting lost in the complex geometry of the whole graph, you just need to ask: "How many independent, high-probability 'witnesses' can I pack into this group?"

The more witnesses you can pack, the exponentially smaller the chance that the whole group gets cut off from the infinite world. It turns a complex, global problem into a simple, local counting game.

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