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An Elementary Proof of a Remarkable Relation Between the Squircle and Lemniscate

This paper provides an elementary proof using basic integral calculus and a geometric interpretation for a generalized relation connecting the areas of sectors of the squircle (x4+y4=1x^4+y^4=1) to the arc lengths of segments of the lemniscate, extending the known connection between their total area and length without relying on elliptic integrals or the gamma function.

Original authors: Zbigniew Fiedorowicz, Muthu Veerappan Ramalingam

Published 2026-06-03
📖 5 min read🧠 Deep dive

Original authors: Zbigniew Fiedorowicz, Muthu Veerappan Ramalingam

Original paper licensed under CC BY 4.0 (http://creativecommons.org/licenses/by/4.0/). This is an AI-generated explanation of the paper below. It is not written or endorsed by the authors. For technical accuracy, refer to the original paper. Read full disclaimer

The Big Picture: Two Strange Shapes and a Secret Connection

Imagine you have two very unusual shapes drawn on a piece of paper.

  1. The Squircle: This is a "square circle." It looks like a circle that has been gently squashed into a square shape. Mathematically, it's defined by the equation x4+y4=1x^4 + y^4 = 1.
  2. The Lemniscate: This looks like a figure-eight or a twisted infinity symbol (\infty). It's defined by the equation (x2+y2)2=x2y2(x^2 + y^2)^2 = x^2 - y^2.

For a long time, mathematicians knew there was a mysterious link between these two shapes. Specifically, they knew that the total area inside the squircle and the total length of the lemniscate were related by a specific number: 2\sqrt{2} (roughly 1.414).

However, the old proofs for this were like trying to solve a puzzle using a sledgehammer. They required advanced, complex math (elliptic integrals and gamma functions) that only experts could understand.

The authors of this paper, Zbigniew Fiedorowicz and Muthu Veerappan Ramalingam, have found a "simple" way to prove this. They used basic calculus (the kind taught in high school or early college) to show that this relationship isn't just about the total size of the shapes, but about how they grow together, piece by piece.

The Story of the Two Runners

To understand the proof, imagine two runners on two different tracks.

  • Runner A (The Squircle Runner): This runner is on the "Squircle" track. They are running in a special way called "Keplerian motion." Imagine a planet orbiting a star; as it gets closer to the star, it speeds up, and as it gets farther away, it slows down, but it sweeps out equal areas in equal amounts of time. Our runner does the same thing: they sweep out a "pie slice" of area at a constant rate.
  • Runner B (The Lemniscate Runner): This runner is on the "Lemniscate" (figure-eight) track. They are running at a constant speed (uniform motion), just like a car on a highway.

The Magic Discovery:
The paper proves that if you start both runners at the same time, there is a perfect synchronization between them.

If Runner A sweeps out a specific amount of area on the squircle, Runner B will have traveled a specific distance along the lemniscate. The relationship is:

The distance Runner B travels is exactly 2\sqrt{2} times the area Runner A sweeps out.

It's as if the "area" on one shape is secretly the same thing as "distance" on the other shape, just scaled by a factor of 2\sqrt{2}.

The "Projection" Trick

How do they prove this? They use a geometric trick involving a "shadow" or a "projection."

  1. Pick a point on the Squircle.
  2. Draw a line from the center of the shape through that point until it hits the Lemniscate.
  3. The paper shows that if you look at the distance from the center to the point on the Lemniscate, and square it, it relates perfectly to the position of the point on the Squircle.

The authors show that if you take the area of the "pie slice" on the squircle and multiply it by 2\sqrt{2}, it equals the length of the curve on the lemniscate, provided you measure the lemniscate curve starting from a specific point determined by the squircle's position.

Why is this a "Big Deal"?

Usually, calculating the area of a squircle or the length of a lemniscate involves integrals that are impossible to solve with simple formulas. You usually need a computer or very advanced math to get a number.

The beauty of this paper is that it doesn't just give you a number; it gives you a geometric story. It says, "You don't need to know the whole shape to understand the relationship. Just watch how these two runners move, and you'll see that their movements are locked together by this 2\sqrt{2} rule."

The "Double Cover" Analogy

The paper also mentions a fascinating detail about how these shapes connect.

Imagine the Lemniscate is a loop-de-loop track. The Squircle is a simpler track. The paper suggests that if you map the Squircle onto the Lemniscate, the Squircle has to go around twice to make the Lemniscate go around once.

Think of it like a gear system:

  • The Squircle is a small gear with 2 teeth.
  • The Lemniscate is a large gear with 1 tooth.
  • As the small gear turns once, the large gear turns half a time. But because of the way the math works, the "runner" on the Lemniscate actually completes a full lap while the "sweeper" on the Squircle does two laps.

Summary of the Results

  1. The Main Theorem: There is a direct, point-by-point link between the area of a sector on the squircle and the arc length on the lemniscate.
  2. The Formula: If AA is the area on the squircle and LL is the corresponding length on the lemniscate, then L=A×2L = A \times \sqrt{2}.
  3. The Method: They proved this using only basic calculus (differentiation and integration), avoiding the heavy machinery of advanced analysis.
  4. The "Physics" View: They interpret this as a connection between two types of motion: "Keplerian motion" (sweeping area) on the squircle and "Uniform motion" (constant speed) on the lemniscate.

In short, the paper takes a complex, mysterious mathematical fact and explains it using a simple, visual story of two runners on different tracks who are perfectly synchronized by a factor of 2\sqrt{2}.

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