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A Greatest Common Divisor Criterion of Certain Binomial Coefficients

This paper presents a formal proof, generated by the AI-driven MechMath Agent Team and verified in Lean, of the OEIS A080170 criterion which establishes that the greatest common divisor of specific binomial coefficients equals one if and only if the quotient of n=k+1n=k+1 by its largest prime-power factor exceeds that factor.

Original authors: Dakai Guo, Ruichen Qiu, Yichuan Cao, Ruyong Feng, Xiao-Shan Gao

Published 2026-06-23
📖 5 min read🧠 Deep dive

Original authors: Dakai Guo, Ruichen Qiu, Yichuan Cao, Ruyong Feng, Xiao-Shan Gao

Original paper licensed under CC BY 4.0 (http://creativecommons.org/licenses/by/4.0/). This is an AI-generated explanation of the paper below. It is not written or endorsed by the authors. For technical accuracy, refer to the original paper. Read full disclaimer

The Big Picture: A Digital Detective Story

Imagine you have a giant, infinite library of number patterns called the OEIS (The On-Line Encyclopedia of Integer Sequences). It's like a massive catalog where mathematicians write down interesting lists of numbers they've found.

For a long time, one specific entry in this library, labeled A080170, was a mystery. It listed numbers that shared a very special, boring property: they had no common divisors other than 1. (In math terms, their "Greatest Common Divisor" is 1).

The library had a guess (a conjecture) about why these numbers behaved this way. It suggested that the answer depended on the "building blocks" of the number right next to it. But nobody had proven the guess was true. It was just a hunch.

This paper is the story of how a team of human mathematicians and an AI agent called MechMath solved this mystery, proved the guess was correct, and even built a "robot proof" that a computer could check to ensure no mistakes were made.

The Puzzle: The "Binomial" Lock

To understand the puzzle, imagine you have a special lock made of Binomial Coefficients. You might know these as the numbers in Pascal's Triangle (the triangle of numbers used to calculate probabilities or expand algebraic expressions).

The puzzle asks: If you take a specific number, let's call it kk, and look at a specific row of numbers generated by multiplying kk by different numbers (2k,3k,4k...2k, 3k, 4k...), do all those resulting numbers share a common factor?

  • The Question: Is the "Greatest Common Divisor" (GCD) of all these numbers equal to 1? (Meaning, do they have no shared factors?)
  • The Guess: The guess said, "Yes, the GCD is 1 if and only if the number next to kk (which is k+1k+1) has a specific shape."

The Shape of the Number: The "Tallest Tower" Analogy

To understand the condition, imagine the number n=k+1n = k + 1 is a castle built out of prime number bricks (like 2, 3, 5, 7, etc.).

Every number can be broken down into these bricks. For example, if n=12n = 12, it's made of 2×2×32 \times 2 \times 3.

  • The "bricks" come in stacks. You have a stack of 2s (height 2) and a stack of 3s (height 1).
  • The paper focuses on the tallest stack of identical bricks. In the case of 12, the tallest stack is the two 2s.

The Rule (The Criterion):
The paper proves that the GCD is 1 (the lock is "open") if and only if the rest of the castle (the part not in the tallest stack) is bigger than the tallest stack itself.

  • If the rest of the castle is huge: The lock opens (GCD = 1).
  • If the tallest stack is as big as or bigger than the rest: The lock stays closed (GCD > 1).

How They Solved It: The AI and the Human Team

This wasn't just a human scribbling on a napkin. The authors used MechMath, an AI agent designed to do math.

  1. The Human-AI Partnership: The human authors built the AI agent. The agent then generated two things simultaneously:

    • A natural language proof (like the one you are reading now, but written in standard math English).
    • A formal proof written in a computer language called Lean.
  2. The "Robot" Check: The Lean proof is like a set of instructions for a robot. The robot reads every single logical step. If the robot finds a gap or a mistake, it stops and says "Error." If it finishes without errors, the proof is 100% verified.

    • This is important because human proofs can sometimes have tiny, invisible errors. The "robot proof" removes that doubt.
  3. The Tools Used:

    • Newton Interpolation: Think of this as a way to predict the shape of a curve by looking at the gaps between points. The team used this to show that any shared factor must be related to the number k+1k+1.
    • Lucas' Theorem: This is a famous rule about how numbers behave when you look at them in different "bases" (like looking at a number in base 10 vs. base 2). The team used this to break the problem down into tiny, manageable "digit boxes."
    • Digit Boxes: Imagine a grid of numbers. The team proved that if you try to shift this grid by a certain amount, the numbers will only stay inside the grid if the shift is "zero" (or a very specific type of zero). This helped them prove the final condition about the "tallest stack."

The Result: A New Entry in the Hall of Fame

The paper concludes with a victory lap:

  • They proved Ralf Stephan's guess (Conjecture 17) was correct.
  • They updated the Formal Conjectures project, a benchmark for AI and math.
  • Before this, the project had 96 unsolved problems and 4 solved ones.
  • After this paper, it has 95 unsolved and 5 solved.

Summary in One Sentence

This paper uses a team of humans and an AI to prove a long-standing guess about when a specific group of numbers shares no common factors, using a "tallest tower" rule and verifying the result with a computer-checkable robot proof.

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