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A Stretched-Exponential Bound for an Erdos--Graham Unit-Fraction Problem

This paper proves a stretched-exponential bound, ε(A)exp(cKlogK)\varepsilon(A)\leq \exp\bigl(-c\sqrt{K\log K}\bigr), for the distance from 1 to the largest reciprocal subsum of a finite multiset of positive integers with total reciprocal sum exceeding KK, thereby improving upon the quadratic bound established by Erdős and Graham and providing significant progress toward their conjecture of a pure exponential decay.

Original authors: Samuel Korsky

Published 2026-07-07
📖 5 min read🧠 Deep dive

Original authors: Samuel Korsky

Original paper licensed under CC BY 4.0 (http://creativecommons.org/licenses/by/4.0/). This is an AI-generated explanation of the paper below. It is not written or endorsed by the authors. For technical accuracy, refer to the original paper. Read full disclaimer

The Big Picture: The "Perfect 1" Puzzle

Imagine you have a giant bag of different-sized Lego bricks. Each brick has a number on it, like 2, 3, 5, or 100. The rule of the game is that the "value" of a brick is 1 divided by its number.

  • A brick labeled "2" has a value of 1/2.
  • A brick labeled "3" has a value of 1/3.
  • A brick labeled "100" has a value of 1/100.

The Goal: You want to pick a handful of these bricks and stack them together so their total value is exactly 1.

The Problem: Sometimes, no matter how many bricks you have, you can't get the stack to equal exactly 1. You might get very close—like 0.999—but you miss the mark. The paper asks: If you have a huge pile of bricks (a lot of "mass"), how close can you get to 1 without hitting it exactly?

The Old Guess vs. The New Discovery

Mathematicians Paul Erdős and Ronald Graham looked at this problem years ago. They proved that if your pile of bricks is big enough, you can't miss the target by much. They showed the gap (the distance between your stack and 1) gets smaller as the pile gets bigger, but they thought it might shrink very fast—like an exponential curve (think of a ball dropping and bouncing, getting smaller and smaller very quickly).

They asked: Is it true that the gap shrinks super-fast, like eKe^{-K}?

The Answer in this Paper:
The author, Samuel Korsky, says: "Not quite that fast, but still incredibly fast."
He proves that the gap shrinks at a "stretched-exponential" rate.

  • The Analogy: Imagine the "perfect 1" is a target on a wall.
    • The old guess was that if you double your number of bricks, your aim gets exponentially better (you get infinitely closer).
    • Korsky proves that your aim gets better at a rate that is almost exponential, but slightly "stretched" out. It's like running a race where you get faster and faster, but you have to run a slightly longer distance to reach that top speed.
    • Mathematically, the gap is roughly eKlogKe^{-\sqrt{K \log K}}. This is still a tiny, tiny number for large piles, meaning you are almost guaranteed to hit 1 if you have enough bricks.

How Did He Solve It? (The Three-Step Strategy)

To prove this, the author had to deal with a chaotic mess of numbers. He used a clever three-step process to organize the chaos.

1. The "Compression" (Folding the Map)

Imagine you have a messy pile of bricks where you have 100 copies of the "1/100" brick.

  • The Trick: The author realized that 100 copies of "1/100" is the same as 10 copies of "1/10". And 10 copies of "1/10" is the same as 1 copy of "1/1".
  • The Action: He systematically "compressed" the pile. If he saw enough small bricks to make a bigger one, he swapped them out for the bigger one.
  • The Result: He turned a messy, huge pile into a "stable" pile where no number appears too many times. This made the math much easier to handle, like folding a giant map into a small pocket size.

2. The "Random Activation" (The Dice Roll)

Now, he needed to show that in this "stable" pile, there must be a combination that hits 1.

  • The Analogy: Imagine you are trying to find a specific combination of ingredients to bake a cake. Instead of checking every single recipe, you decide to randomly pick ingredients.
  • The Method: He used a mathematical "dice roll" (probability). He asked: "If I randomly pick a subset of these compressed bricks, what is the chance the total is close to 1?"
  • The Insight: He proved that if the pile is big enough, the "random picks" will inevitably land in the "danger zone" (the tiny gap just below 1). If they land there, it means a perfect combination must exist.

3. The "Divisor Sorting" (Organizing the Chaos)

The hardest part was dealing with "composite" numbers (numbers made of smaller numbers, like 6, 12, 15). These are tricky because they share factors with other numbers.

  • The Analogy: Imagine trying to sort a pile of mixed-up keys. Some keys open many doors; some open only one.
  • The Method: He created a system to sort these "keys" (numbers) based on how many other numbers they divide. He separated the "easy" numbers (primes) from the "hard" numbers (composites).
  • The Result: By sorting them, he could prove that the "hard" numbers didn't mess up the math enough to prevent the "random pick" from hitting the target.

The "AI" Twist

At the very end of the paper, the author includes a unique note: He used AI (GPT-5.5 Pro) to help write the proof.

  • What the AI did: The author came up with the big ideas (the compression, the random strategy, the main logic). The AI helped fill in the boring, difficult technical details, checked the math constants, and helped write the code to verify the complex steps.
  • The Human Role: The author took full responsibility for the final result, verifying that the AI didn't make any mistakes. It's like an architect designing a building and using a robot to help lay the bricks and check the measurements.

Summary

The paper solves a 50-year-old puzzle about adding fractions. It proves that if you have a large enough collection of unit fractions, you can get extremely close to a sum of 1. The gap between your sum and 1 shrinks incredibly fast (a "stretched exponential" rate). The author solved this by compressing the numbers, using probability to find the solution, and sorting the difficult numbers, with significant help from AI to handle the heavy mathematical lifting.

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