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On concatenations of two kk-generalized Pell numbers

This paper proves that the concatenation of two kk-generalized Pell numbers equals a third such number only in the specific case where k=2k=2 and the numbers are 1 and 2, while no solutions exist for k3k \ge 3.

Original authors: Cherif B. Deme, Kancou D. Fall, Khady Faye, Bernadette Faye

Published 2026-06-16
📖 4 min read🧠 Deep dive

Original authors: Cherif B. Deme, Kancou D. Fall, Khady Faye, Bernadette Faye

Original paper licensed under CC BY 4.0 (http://creativecommons.org/licenses/by/4.0/). This is an AI-generated explanation of the paper below. It is not written or endorsed by the authors. For technical accuracy, refer to the original paper. Read full disclaimer

Imagine you have a special machine that generates a sequence of numbers, like a digital counter that follows a very strict set of rules. In this paper, the authors are investigating a specific type of number generator called k-generalized Pell numbers.

Think of these numbers as a family of sequences. The most famous member of this family is the "classic" Pell sequence (where k=2k=2), which grows by adding the previous number to twice the one before it. But this family has many other versions (where k=3,4,5k=3, 4, 5, etc.), each with slightly different rules for how fast they grow.

The Big Question: The "Glue" Test

The authors wanted to solve a puzzle: Can you take two numbers from this sequence and "glue" them together to make a third number from the same sequence?

In math terms, "gluing" means concatenation. If you have the number 1 and the number 2, gluing them makes 12. If you have 5 and 5, you get 55.

The equation they are testing looks like this:
NumberA=NumberB glued to NumberC \text{Number}_A = \text{Number}_B \text{ glued to } \text{Number}_C

For example, if you take the 4th number in the classic sequence (which is 12), can you find two other numbers in that same sequence that, when glued together, make 12?

  • Yes! The 1st number is 1, and the 2nd number is 2. Glue them: 1 and 2 become 12.
  • So, 12=1212 = 1 \parallel 2 is a solution.

The Investigation

The authors spent the paper trying to find all possible solutions to this "glue" puzzle for every version of the sequence (every value of kk).

Here is how they broke it down:

1. The "Small Numbers" Check (k=2k=2)
First, they looked at the classic sequence (k=2k=2). They found that the only time this "glue" trick works is the one example mentioned above: 12 is made of 1 and 2. No other numbers in this classic sequence can be formed by gluing two others together.

2. The "Big Numbers" Check (k3k \ge 3)
Next, they looked at the more complex versions of the sequence (where kk is 3 or higher). These sequences grow much faster and behave differently.

  • The Hypothesis: They suspected that for these complex sequences, the "glue" trick never works.
  • The Proof: They used a powerful mathematical toolkit involving:
    • Crystal Ball Math (Binet Formulas): Formulas that predict exactly what a number in the sequence will be without having to count up one by one.
    • The "Too Big to Count" Problem: They proved that if a solution existed, the numbers would have to be astronomically huge—so huge that they would break the laws of how these sequences grow.
    • The "Mathematical Squeeze" (Reduction): Since they couldn't check every single huge number, they used advanced techniques (like the LLL algorithm and continued fractions) to "squeeze" the possible answers down. They showed that even if a solution existed, it would have to be smaller than a certain limit.
    • The Final Sweep: Once they squeezed the possibilities down to a manageable size, they used computers to check every single remaining candidate.

The Result

After all the heavy lifting, the conclusion was definitive:

  • For the classic sequence (k=2k=2): There is exactly one solution: 12=1212 = 1 \parallel 2.
  • For all other sequences (k3k \ge 3): There are zero solutions. You cannot glue two numbers from these sequences together to get another number from the same sequence.

In Simple Metaphors

Imagine the k-generalized Pell numbers as different types of Lego bricks.

  • The Classic (k=2k=2) bricks are special. You can snap a small "1" brick and a small "2" brick together to perfectly form a "12" brick. But that's the only time this works.
  • The Complex (k3k \ge 3) bricks are shaped differently. The authors proved that no matter how you try to snap two of these bricks together, they will never form a shape that matches another brick in the set. The shapes just don't fit that way.

Summary: The paper proves that the "gluing" phenomenon is a rare quirk that only happens once in the classic version of these numbers and never happens in any of the more complex variations.

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